16x^2+10x-27=2x+8

Solution for 16x^2+10x-27=2x+8 equation:

16x^2+10x-27=2x+8

We move all terms to the left:

16x^2+10x-27-(2x+8)=0

We get rid of parentheses

16x^2+10x-2x-8-27=0

We add all the numbers together, and all the variables

16x^2+8x-35=0

a = 16; b = 8; c = -35;
Δ = b2-4ac
Δ = 82-4·16·(-35)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-48}{2*16}=\frac{-56}{32}
=-1+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+48}{2*16}=\frac{40}{32}
=1+1/4
$